Is 0.9 recurring equal to 1?

The place for chatting and discussing subjects unrelated to Wesnoth.

Moderators: Forum Moderators, Developers

User avatar
Zarel
Posts: 700
Joined: July 15th, 2009, 8:24 am
Location: Minnesota, USA
Contact:

Re: Is 0.9 recurring equal to 1?

Post by Zarel » July 7th, 2010, 4:44 pm

Sgt. Groovy wrote:Like wave and particle? :P
I said "not sure" and "seem". I didn't dismiss the possibility entirely. :|
Proud creator of the :whistle: smiley | I prefer the CC-0 license.

Tonepoet
Posts: 184
Joined: November 18th, 2005, 2:54 pm
Contact:

~

Post by Tonepoet » July 8th, 2010, 11:12 pm

Sgt. Groovy wrote:Don't put words in my mouth, I never said anything about 0.999..., my ramblings were an answer to a totally different question.
Does he have to? It's a very easy conclusion to infer, since it is inherent to the nature of the given answers answers given that 0 is the only infinitely small value. Otherwise the orientation of .9~ changes because the difference of 0 wouldn't be the infinity a sequence of .9~ approaches but rather ε.

The only way we could avoid this is if the value isn't sequentially oriented but even then we have the problem of actually placing .9~ in the sequence, as we have very few ways to determine if anything comes after it to actually place it in the sequence, since it comes before itself and it comes after itself giving it infinitesimally cardinal value. We just can't because infinity itself is a constant. The concept of placing .9~ seems contradictory to the nature of infinity just as much as whatever 1-ε is, or 1+ε for that matter. It has multiplicity of self-referring values that never stops.

Therefore I'd suggest:

If ε, then .9~ < 1.

I'd also suggest that:

Numbers are representations known as quantifiers.
Quantifiers quantify.
Therefore anything with a number is quantified.

Numbers can be used to represent points.
If one number represents a point, all numbers must represent a point in relation.
Points are infinitesimally small by definition.

Therefore infinitesimal smallness and quantification are not mutually contradictory.

It also shows a very basic fundamental application of concept ε may already be used in standard mathematics, albeit perhaps not directly in the numbering system. [*coughs* Although I'd suggest a name change for the decimal point in that case.]

Also just today I was reading a very interesting little article about the developmental history of math, the concept of a number zero and how that changed the conventional landscape of math. It was very interesting, however I don't want to link that here due to the potential touchiness of some of the subject matter it contains. It gave a very brief description of the Neumann Hierarchy, which I thought seemed particularly relevant, especially since we're now talking about alternative numbering systems. Would anybody care to go into greater detail as to what that is?
Htonsew Rof Elttab Eht is just too cool for school. I've got no words to describe it. Have any of you guys tried it? ;-)

Cracky6711
Posts: 2
Joined: January 10th, 2011, 8:33 pm

Re: Is 0.9 recurring equal to 1?

Post by Cracky6711 » January 10th, 2011, 8:39 pm

so 0.999 + 0.001 = 1 right? and 0.99999999 + 0.00000001 = 1 and 0.99999999999999999 + 0.00000000000000001=1 and i could go on infiniteley until 0.00000000000000000000000000000001 has so many zeros before the 1 it might as well be 0. but however many 9s you put after 0.999999 there is still going to be an answer which is along the lines of 0.000001, think about it. Think of it as you have infinite number of 9s, but then you put an extra 9 on, so you have to put another 0 on, and this becomes infinitesimally small.

The problem we have is that infinity in itself is an imaginary number, just as is every single recurring number. think about it, infinity is impossible in itself. Also, it is impossible to type on a calculator 0.0r1, because wherever you put the 1, you can always put an extra 0 before it.

Its impossible for infinite 0.9 to ever equal 1, because there will always be a difference of 0.0r with a 1 on the end.
In my opinion, 0.9r is equal to 0.0r with a 1 at the end.

User avatar
Vranca
Posts: 218
Joined: August 27th, 2010, 8:58 pm

Re: Is 0.9 recurring equal to 1?

Post by Vranca » January 10th, 2011, 9:15 pm

You just necroed this thred,the last post was 09 Jul 2010...
In my opinion, 0.9r is equal to 0.0r with a 1 at the end.
But if it is requiring it does not end.
form wiki
My sprites,My Minitroops
Philip II of Macedon:"If I win this war, you will be slaves forever."
The Spartan ephors:"If."
Subsequently, both Philip and Alexander would avoid Sparta entirely.

Cracky6711
Posts: 2
Joined: January 10th, 2011, 8:33 pm

Re: Is 0.9 recurring equal to 1?

Post by Cracky6711 » January 10th, 2011, 10:33 pm

Vranca wrote:You just necroed this thred,the last post was 09 Jul 2010...
In my opinion, 0.9r is equal to 0.0r with a 1 at the end.
But if it is requiring it does not end.
form wiki
ok i misfrased that...basically what i mean is that 1 - 0.9r = an infinitesimal value (the smallest possible positive value above 0)

Joram
Posts: 366
Joined: September 2nd, 2008, 5:36 am

Re: Is 0.9 recurring equal to 1?

Post by Joram » January 11th, 2011, 3:23 am

Its impossible for infinite 0.9 to ever equal 1, because there will always be a difference of 0.0r with a 1 on the end.
Only if the number of 9's is finite. But since 0.999... goes on forever, there will never be a 1 to add.

Think about it. No matter how far back you put the 1, there will be 9's beyond it. Therefore, the supposed number that added to 0.999... equals 1 does not exist; not even as an infinitesimal value.
The Fires of Pride 0.3, a heavily story based campaign.
On hold while I try and finish my book

User avatar
shadowm
Site Administrator
Posts: 6573
Joined: November 14th, 2006, 5:54 pm
Location: Chile
Contact:

Re: Is 0.9 recurring equal to 1?

Post by shadowm » January 11th, 2011, 6:04 am

Vranca wrote:You just necroed this thred,the last post was 09 Jul 2010...
Emphasis mine.

Locked.
Author of the unofficial UtBS sequels Invasion from the Unknown and After the Storm.

Locked